# Line slope calculator x-5y=-12

**Straight line given by points A[3; 3] and B[8; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+2.4

**Canonical form of the line equation:**x-5y+12 = 0

**Parametric form of the line equation:**

x = 5t+3

y = t+3 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -12

**Y intercept:**y

_{0}= q = 2.4

**Distance line from the origin:**d

_{0}= 2.3534

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[5.5; 3.5]

**Perpendicular Bisector equation:**5x+y-31 = 0

**Vector OA = (3; 3) ; |OA| = 4.2426**

**Vector OB = (8; 4) ; |OB| = 8.9443**

**Scalar product OA .OB = 36**

**Angle ∠ AOB = 18°26'6″ = 0.3218 rad**